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20x^2+0x-90=0
We add all the numbers together, and all the variables
20x^2+x-90=0
a = 20; b = 1; c = -90;
Δ = b2-4ac
Δ = 12-4·20·(-90)
Δ = 7201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{7201}}{2*20}=\frac{-1-\sqrt{7201}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{7201}}{2*20}=\frac{-1+\sqrt{7201}}{40} $
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